leetcode 1094 - Car Pooling

https://leetcode.com/problems/car-pooling/

You are driving a vehicle that has capacity empty seats initially available for passengers. The vehicle only drives east (ie. it cannot turn around and drive west.)

Given a list of trips, trip[i] = [num_passengers, start_location, end_location] contains information about the i-th trip: the number of passengers that must be picked up, and the locations to pick them up and drop them off. The locations are given as the number of kilometers due east from your vehicle’s initial location.

Return true if and only if it is possible to pick up and drop off all passengers for all the given trips.

Example 1:

Input: trips = [[2,1,5],[3,3,7]], capacity = 4
Output: false
Example 2:

Input: trips = [[2,1,5],[3,3,7]], capacity = 5
Output: true
Example 3:

Input: trips = [[2,1,5],[3,5,7]], capacity = 3
Output: true
Example 4:

Input: trips = [[3,2,7],[3,7,9],[8,3,9]], capacity = 11
Output: true

Constraints:

trips.length <= 1000
trips[i].length == 3
1 <= trips[i][0] <= 100
0 <= trips[i][1] < trips[i][2] <= 1000
1 <= capacity <= 100000

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class Solution {
public:
struct Trip {
bool start;
int num;
int location;

Trip(bool s, int n, int l) {
start = s;
num = n;
location = l;
}
};

bool carPooling(vector<vector<int>>& trips, int capacity) {
vector<Trip> all_trips;

for (auto v : trips) {
all_trips.push_back(Trip(true, v[0], v[1]));
all_trips.push_back(Trip(false, v[0], v[2]));
}

auto mycomp = [](const Trip &t1, const Trip &t2) {
if (t1.location < t2.location) return true;
if (t1.location > t2.location) return false;
return t1.start < t2.start;
};

sort(all_trips.begin(), all_trips.end(), mycomp);

int total = 0;

for (auto t : all_trips) {
if (t.start)
total += t.num;
if (total > capacity)
return false;
if (!t.start)
total -= t.num;
}

return true;
}
};